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5/4x-1+-1/(4x-1)^2=4
We move all terms to the left:
5/4x-1+-1/(4x-1)^2-(4)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: (4x-1)^2!=0determiningTheFunctionDomain 5/4x-1/(4x-1)^2-1-4+=0
x∈R
We add all the numbers together, and all the variables
5/4x-1/(4x-1)^2=0
We calculate fractions
(5*(4x-1)^2)/(4x*(4x-1)^2)+(-4x)/(4x*(4x-1)^2)=0
We calculate terms in parentheses: +(5*(4x-1)^2)/(4x*(4x-1)^2), so:
5*(4x-1)^2)/(4x*(4x-1)^2
We multiply all the terms by the denominator
5*(4x-1)^2)
We multiply parentheses
20x+
We add all the numbers together, and all the variables
20x
Back to the equation:
+(20x)
We calculate terms in parentheses: +(-4x)/(4x*(4x-1)^2), so:We get rid of parentheses
-4x)/(4x*(4x-1)^2
We multiply all the terms by the denominator
-4x)
Back to the equation:
+(-4x))
20x-4x)=0
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